We give sufficient conditions on a symmetric tensor S ∈ SdFn to satisfy the following
equality: the symmetric rank of S, denoted as srank S, is equal to the rank of S, denoted as rank S.
This is done by considering the rank of the unfolded S viewed as a matrix A(S). The condition is
rank S∈{rank A(S), rank A(S)+1}. In particular, srank S = rank S for S ∈ SdCn for the cases
(d, n) ∈ {(3, 2), (4, 2), (3, 3)}. We discuss the analogues of the above results for border rank and best
approximations of symmetric tensors.